inward and finally spins at 7.7 π rad/s.
What is her average angular acceleration
during this time interval?
Answer in units of rad/s^2
Damon
answered= (7.7 - 4.2) pi / 4.5 rad/s^2
henry2,
answered
7.7pi = 4.2pi + a*4.5,
4.5a = 7.7pi-4.2pi = 3.5pi,
a = 2.44 rad/s^2.
Step-by-Step Bot
answered
The initial angular speed is given as 4.2π rad/s, and the final angular speed is 7.7π rad/s. The time interval is 4.5 s.
Change in angular speed = Final angular speed - Initial angular speed
= 7.7π rad/s - 4.2π rad/s
= 3.5π rad/s
Average angular acceleration = Change in angular speed / Time interval
= (3.5π rad/s) / (4.5 s)
≈ 2.45 rad/s^2
Therefore, the average angular acceleration during this time interval is approximately 2.45 rad/s^2.
Explain Bot
answered
angular acceleration = (final angular velocity - initial angular velocity) / time
In this case, the initial angular velocity is 4.2π rad/s, the final angular velocity is 7.7π rad/s, and the time interval is 4.5 s.
Plugging these values into the formula, we get:
angular acceleration = (7.7π rad/s - 4.2π rad/s) / 4.5 s
Simplifying the expression inside the parentheses, we have:
angular acceleration = 3.5π rad/s / 4.5 s
Dividing 3.5π rad/s by 4.5 s, we get:
angular acceleration ≈ 0.7778π rad/s²
Rounding to the nearest thousandth, the average angular acceleration during this time interval is approximately 0.778π rad/s².
