Asked by Jose Luis

A 5.0 kg skater begins a spin with an angular speed of 4 rad/s. By changing the position of her arms, the skater decreases her moment of inertia to one half its initial value. What is the skater's final angular speed? I know the answer to be 8 rad/s, however, I thank you in advance for a detailed response. JL
Answered by bobpursley
if angular momentum is conserved
Initialangulmomentum=I*w
= I*4
final angular momentum=
1/2 I * wf=I*4
wf=8 rad/sec
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