Asked by Charles

An aeroplane leaves an airport A and flies on a bearing 035°for 1.5 hours at 600km/hr to airport B It then flies on a bearing 130° for 1.5hours at 400km per hour to an airport C calculate the distance from C to A and the bearing of C from A with the diagram of the bearing
Answered by Reiny
distance AB = (1.5)(600) km or 900 km
distance BC = 1.5(400) km or 600 km
I assume you drew your diagram correctly.
So now you have triangle ABC with AB = 900, BC = 600 and angle B = 75°

Use the cosine law to find AC

Let me know what you did, and what your answer is.
Answered by henry2,
AB = 900km[35o].
BC = 600km[130o].
AC = ?

AC = AB + BC. = 900[35o] + 600[130o]..
AC = (900*sin35+600*sin130) + (900*cos35+600*cos130)I,
AC = 975.8 + 351.6i = 1037km[70.2o].
Bearing of 70.2 Degrees.

Answered by Tari
Teach me I wan the particular answer of this question plss
Answered by Andrea
D diagram of d question is not here
Answered by Andrea
D diagram wic answers d question is not here
Answered by Presh
How did you get 900km and 600km?
Answered by Godswill
Explain more
Answered by Prspix Fernandinho R.
Thanks so much.this explanation was simple to understand and it helped me.
Answered by Favour
Pleses can u explain more
Answered by connexus forever
hu
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