Question

An aeroplane leaves an airport A and flies on a bearing 035°for 1.5 hours at 600km/hr to airport B It then flies on a bearing 130° for 1.5hours at 400km per hour to an airport C calculate the distance from C to A and the bearing of C from A with the diagram of the bearing

Answer 1

distance AB = (1.5)(600) km or 900 km
distance BC = 1.5(400) km or 600 km
I assume you drew your diagram correctly.
So now you have triangle ABC with AB = 900, BC = 600 and angle B = 75°

Use the cosine law to find AC

Let me know what you did, and what your answer is.

Answer 2

AB = 900km[35o].
BC = 600km[130o].
AC = ?

AC = AB + BC. = 900[35o] + 600[130o]..
AC = (900*sin35+600*sin130) + (900*cos35+600*cos130)I,
AC = 975.8 + 351.6i = 1037km[70.2o].
Bearing of 70.2 Degrees.

Answer 3

Teach me I wan the particular answer of this question plss

Answer 4

D diagram of d question is not here

Answer 5

D diagram wic answers d question is not here

Answer 6

How did you get 900km and 600km?

Answer 7

Explain more

Answer 8

Thanks so much.this explanation was simple to understand and it helped me.

Answer 9

Pleses can u explain more

Answer 10

hu