Asked by Mercy
                an aeroplane leaves an airport,flies due north for two hours at 500km/hr.it then flies 450km on a bearing 053.how far is the plane from the airport and what is its bearing from bearing from east
            
            
        Answers
                    Answered by
            Steve
            
    1st leg goes (0,2*500) = (0,1000)
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N
    
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N
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