Asked by Mercy
an aeroplane leaves an airport,flies due north for two hours at 500km/hr.it then flies 450km on a bearing 053.how far is the plane from the airport and what is its bearing from bearing from east
Answers
Answered by
Steve
1st leg goes (0,2*500) = (0,1000)
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.