Asked by Mercy
an aeroplane leaves an airport,flies due north for two hours at 500km/hr.it then flies 450km on a bearing 053.how far is the plane from the airport and what is its bearing from bearing from east
Answers
Answered by
Steve
1st leg goes (0,2*500) = (0,1000)
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N
2nd leg goes (450sin53°,450cos53°) = (359,271)
so, the plane ends up at (359,1271)
The distance is thus 1321 @ E74°N