Unless #2 is faster than #1, it will never overtake it.
In the 45 minutes #2 has been waiting, #1 has gone 450 km.
So, if #2 is x km/hr faster than #1, it will overtake #1 in 450/x hours
In the 45 minutes #2 has been waiting, #1 has gone 450 km.
So, if #2 is x km/hr faster than #1, it will overtake #1 in 450/x hours
Let's assume that Jet #1 starts at time t = 0, and Jet #2 starts 3/4 of an hour later, at t = 3/4.
The distance traveled by Jet #1 can be calculated using the formula: distance = speed × time. In this case, the speed of Jet #1 is 600 km/h, and time is the variable we are looking for.
So the distance traveled by Jet #1 is:
distance1 = 600 km/h × time
Now let's calculate the distance traveled by Jet #2. Since Jet #2 starts 3/4 of an hour later than Jet #1, its time will be (time + 3/4).
The distance traveled by Jet #2 is then:
distance2 = 600 km/h × (time + 3/4)
For Jet #2 to overtake Jet #1, it needs to travel the same distance. Therefore, we can set distance1 equal to distance2 and solve for time:
600 km/h × time = 600 km/h × (time + 3/4)
We can simplify the equation by canceling out the common terms:
time = (time + 3/4)
To solve for time, we can subtract time from both sides:
0 = 3/4
This equation has no solution. It means that Jet #2 will never overtake Jet #1 if they are traveling at those speeds and starting at those times.
Note: There might be some issues or errors in the initial problem statement or calculations. Please double-check the given information to ensure accurate results.