Question

(1). An Aeroplane leaves an airport, flies due North for 2 hrs at 500km/h. It then flies on a bearing of 053 degree at 300km/h for 90 mins. How far is the plane from the airport correct to 1 dp
(2). Find the bearing of the plane from the Airport correct to 1 dp.
30 points
(3). If it takes the Aeroplane 150 mins to fly back to the airport. Find the average speed of the aeroplane for the whole flight correct to 1dp.

Answer 1

(1) you fly on a <u>heading</u>, not a bearing. The law of cosines is the way to find this value. Since distance = speed*time,
z^2 = 1000^2 + 450^2 - 2(1000)(450)cos53°
(2) Here, "bearing" is correctly used. It is NθE where
tanθ = (450sin53°) / (1000+450cos53°)
(3) avg speed = distance/time
= (1000+450+z)/(2 + 1.5 + 2.5)

Answer 2

I think you first answer is wrong because it supposed to be 1320.7 km.

Answer 3

And also your solution seems to be wrong

Answer 4

Who ever responds first and correctly gets $100