Asked by klli
write an equation in slope intercept form that passes through a given point and is parallel to the graph of the given equation
(3,2) y=x+5 (-2,5), y =-4x+2 and (4,-6), y=-3/4x+1
(3,2) y=x+5 (-2,5), y =-4x+2 and (4,-6), y=-3/4x+1
Answers
Answered by
Reiny
I will do the 2nd, follow the same steps for the others
(-2,5), y =-4x+2
Since your new line is parallel to the given one, their slopes must be the same, that is, the equations will differ only in the y-intercept
let the new equation be
y = -4x + b
but (-2,5) lies on it, so
5 = -4(-2) + b
-3 = b
new equation: y = -4x - 3
(-2,5), y =-4x+2
Since your new line is parallel to the given one, their slopes must be the same, that is, the equations will differ only in the y-intercept
let the new equation be
y = -4x + b
but (-2,5) lies on it, so
5 = -4(-2) + b
-3 = b
new equation: y = -4x - 3
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