Asked by riyas saidkkannu
A close coiled helical spring of round steel wire 10 mm diameter having 10 complete turns with a mean radius of 60 mm is subjected to an axial load of 200 N. Determine the deflection of the spring. C = 80 kN/mm2
Answers
Answered by
Damon
You seem to just want us to do problems for you but give no indication of why you are having trouble.
https://www.quora.com/What-is-the-spring-constant-of-a-coil-spring-in-terms-of-its-physical-parameters
in particular:
The spring constant of a helical spring is given by,
k = G x d^4 / 8 x D^3 x n
Symbols
F = loading of spring
L_o = free spring length
L_s = solid length when gets pressed
k = spring constant
d = diameter of spring wire
D = mean spring diameter
G = modulus of elsticity
n = number of coils
https://www.quora.com/What-is-the-spring-constant-of-a-coil-spring-in-terms-of-its-physical-parameters
in particular:
The spring constant of a helical spring is given by,
k = G x d^4 / 8 x D^3 x n
Symbols
F = loading of spring
L_o = free spring length
L_s = solid length when gets pressed
k = spring constant
d = diameter of spring wire
D = mean spring diameter
G = modulus of elsticity
n = number of coils
Answered by
riyas saidkkannu
Determine the deflection of the spring. C = 80 kN/mm2
Answered by
Ali
Q4/ A helical spring made of steel wire with a diameter of 1 cm has 15 coils with a mean diameter of 10 cm. A 100 N axial load is applied to the spring. Calculate the: A. The maximum shear stress induced, B. The deflection, and C. Stiffened of the spring. Take the modulus of rigidity G= 8.16x10ʻ N/mm².
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