Question
a helical spring fixed by the upper end carries a load of 5kg attached to its lower end .Mass is set into vibration and is measured to make 2 oscillation per seconds .calculate
1.the stiffness of the spring
2.the acceleration at any condition along the spring
1.the stiffness of the spring
2.the acceleration at any condition along the spring
Answers
First of all Period (T) = time/ number of oscillation
T= 1/2= 0.5s
1. Calculate the stiffness of the spring (k)
But T = 2π√m/k
0.5= 6.284√5/k
0.5/6.284=√5/k
(0.0795)²= (√5/k)²
0.006320= 5/k
K= 5/0.06320
K= 791.1N/m
2. acceleration (a) =Force/mass
a= 50/5= 10m/s²
T= 1/2= 0.5s
1. Calculate the stiffness of the spring (k)
But T = 2π√m/k
0.5= 6.284√5/k
0.5/6.284=√5/k
(0.0795)²= (√5/k)²
0.006320= 5/k
K= 5/0.06320
K= 791.1N/m
2. acceleration (a) =Force/mass
a= 50/5= 10m/s²
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