Question
A toy "spring gun" has a spring with a spring constant of 30,000 N/m and is depressed 4 cm. It shoots a plastic dart with a mass of 45 grams. How fast will the dart travel if there is no friction?
Answers
well, the KE of the dart will equal the PE stored in the spring, right?
I'm not really grasping this concept well. I don't know if the KE of the dart is equal is the PE stored? Based on the formulas I don't know that is correct.
PE= 1/2kx^2
k=30,000
x=4cm
KE= 1/2mv^2
m=45g
v=0??
PE= 1/2kx^2
k=30,000
x=4cm
KE= 1/2mv^2
m=45g
v=0??
where else is the stored spring energy going?
the problem says no friction
the problem says no friction
KE = PE
1/2 mv^2 = 1/2 kx^2
Since k is in N/m, we need to use MKS units.
1/2 * 0.045 * v^2 = 1/2 * 30000 * 0.04^2
v = 32.7 m/s
1/2 mv^2 = 1/2 kx^2
Since k is in N/m, we need to use MKS units.
1/2 * 0.045 * v^2 = 1/2 * 30000 * 0.04^2
v = 32.7 m/s
ooooh for some reason I thought I needed to subtract PE and KE and it wasn't making any sense.
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