Asked by John Miller

A light spring with a spring constant of 105.0 N/m rests vertically on the table, as shown in (a) below. A 2.05 g balloon is filled with helium (0°C and 1 atm pressure) to a volume of 4.64 m3 and connected to the spring, causing the spring to stretch, as shown in (b) below. How much does the spring stretch when the system is in equilibrium. (The density of helium is 0.179 kg/m3. The magnitude of the spring force equals kΔx.)
Answered by bobpursley
mass heliium= volume*density
mass baloon given
weight of air displaced=volume*densityair

spring force=volume*densityair-massHe*g-massbaloon*g

how far it stretches=springforce/k
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