A=0.75 m, m=8 kg, k= 400 N/m
ω=sqrt(k/m) = …
x=Acosωt
v= - Aωsinωt
v(max) = Aω
KE=mv²/2 =0.5m A²ω²sinωt
KE(max) = 0.5m A²ω²
A spring, (spring constant of 400 N/m) is displaced .75 m from its equilibrium position. An 8-kg mass is connected to the spring and it is allowed to oscillate horizontally with Simple Harmonic Motion. What is the Kinetic Energy of the mass?
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