no, make sure you adjust the coefficient which controls the period
You will need
y = –3sin (2(x + 15°)) + 5 , notice also that + moves it to the left, - to the right.
The graph of y = –3sin (2x) is shifted to the left by 30° units and up 5 units. Write the new equation.
My answer y= -3sin (2x- 30°) +5
Is this correct?
3 answers
so the answer would be y= -3sin (2x + 30°) +5?
sorry, my error, I was too focused on the 15
your answer will be
y = –3sin (2(x + 30°)) + 5
or
y = –3sin (2x + 60°) + 5
see the graphs here:
https://www.wolframalpha.com/input/?i=plot+y+%3D+%E2%80%933sin+(2x),+y+%3D+%E2%80%933sin+(2x+%2B+%CF%80%2F3)+%2B+5
notice I changed the 60° to π/3 radians
your answer will be
y = –3sin (2(x + 30°)) + 5
or
y = –3sin (2x + 60°) + 5
see the graphs here:
https://www.wolframalpha.com/input/?i=plot+y+%3D+%E2%80%933sin+(2x),+y+%3D+%E2%80%933sin+(2x+%2B+%CF%80%2F3)+%2B+5
notice I changed the 60° to π/3 radians
1 answer