Asked by Kaur
If 3sin^(2)x-7sin x +2=0, x in [0,(pi)/(2)] and
f(n)(theta)=sin^(n) theta + cos^(n) theta. On the basis of above information, the value of
( sin 5 x + sin 4 x)/( 1+ 2 cos 3 x) is:
Here I am not able to find the value of x
i got x = sin^-1(1/3)
What after that????
Please help
f(n)(theta)=sin^(n) theta + cos^(n) theta. On the basis of above information, the value of
( sin 5 x + sin 4 x)/( 1+ 2 cos 3 x) is:
Here I am not able to find the value of x
i got x = sin^-1(1/3)
What after that????
Please help
Answers
Answered by
oobleck
not sure what the f<sub><sub>k</sub></sub>(θ) has to do with anything here, but if sinx = 1/3 then cosx = √8/3
then you can use various multiple-angle formulas to find
sin5x and cos3x
and are those powers in parens exponents, or derivatives?
Usually f<sup><sup>(n)</sup></sup>(x) is the nth derivative
then you can use various multiple-angle formulas to find
sin5x and cos3x
and are those powers in parens exponents, or derivatives?
Usually f<sup><sup>(n)</sup></sup>(x) is the nth derivative
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