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Asked by urgent

solve:
cos^2x - 3sin^2x = 1, -2pi </= x </= 2pi
3 years ago

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Answered by oobleck
cos^2x - 3(1-cos^2x) = 1
4cos^2x = 4
cosx = ±1
now finish it off
3 years ago
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solve:
cos^2x - 3sin^2x = 1, -2pi </= x </= 2pi

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