Asked by Cynthia
Solve cos 2x – 3sin x cos 2x = 0 for the principal value(s) to
two decimal places.
Please explain.
two decimal places.
Please explain.
Answers
Answered by
Steve
cos2x (1 - 3sinx) = 0
cos2x = 0 or sinx = 1/3
cos 2x = 0:
2x = k*pi/2 where k is an integer
x = pi/4, 3pi/4, 5pi/4, 7pi/4
sinx = 1/3:
x = 0.34 or pi-0.34
cos2x = 0 or sinx = 1/3
cos 2x = 0:
2x = k*pi/2 where k is an integer
x = pi/4, 3pi/4, 5pi/4, 7pi/4
sinx = 1/3:
x = 0.34 or pi-0.34
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