Asked by hey222
                Two flat, circular plates are placed on a circular table top. The diameter of each plate is equal to the radius of the table top. Approximately how many square feet of the tabletop or not covered by the plates? Show or explain your work. Use 3.14 for pi
            
            
        Answers
                    Answered by
            Damon
            
    r of plate = r
2 r = R tabletop
area covered = 2 * pi r^2
total area of table = pi R^2 = pi (2r)^2 = 4 pi r^2
so area not covered = 2 pi r^2
    
2 r = R tabletop
area covered = 2 * pi r^2
total area of table = pi R^2 = pi (2r)^2 = 4 pi r^2
so area not covered = 2 pi r^2
                    Answered by
            Henry2,
            
    r = Radius of the table.
r/2 = Radius of each plate.
At = pi * r^2. = Area of table top.
Ap = 2 * (pi * (r/2)^2) = 2 * (pi * r^2/4) = pi*r^2/2. = Area of 2 plates.
A = At - Ap = pi*r^2 - pi*r^2/2 = pi*r^2/2 = Area not covered.
So 1/2 of the area is not covered.
    
r/2 = Radius of each plate.
At = pi * r^2. = Area of table top.
Ap = 2 * (pi * (r/2)^2) = 2 * (pi * r^2/4) = pi*r^2/2. = Area of 2 plates.
A = At - Ap = pi*r^2 - pi*r^2/2 = pi*r^2/2 = Area not covered.
So 1/2 of the area is not covered.
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