Question
A flat uniform circular disk (radius = 2.10 m, mass = 1.00 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a frictionless axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.00 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.60 m/s relative to the ground.
Answers
To find Tangential spped , first you do ...
mvr=1/2MR^2w
and you're solving for w
so basically w=(2mvr)/MR^2
where m= to the mass of the disk(2.10)
r= radius of disk(102)
M=mass of person(40)
R=radius of the person(1.00)
v=tangential speed(2.60)
2(2.6)(1)(40)/(102)(2.10)=w
good luck!
mvr=1/2MR^2w
and you're solving for w
so basically w=(2mvr)/MR^2
where m= to the mass of the disk(2.10)
r= radius of disk(102)
M=mass of person(40)
R=radius of the person(1.00)
v=tangential speed(2.60)
2(2.6)(1)(40)/(102)(2.10)=w
good luck!
This is awful dogshit. Never submit another answer or I will have you banned.
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