Asked by Harry
A flat disk 1.0 m in diameter is oriented so that the plane of the disk makes an angle of pi/6 radians with a uniform electric field. if the field strength is 589.0 N/C, find the electric flux through the surface.
I know that Flux=(integral)|E|cos(theta)dA but I'm not sure how to apply this to this situation or if there is any easier equation to use. Thanks!
I know that Flux=(integral)|E|cos(theta)dA but I'm not sure how to apply this to this situation or if there is any easier equation to use. Thanks!
Answers
Answered by
bobpursley
Flux=area*(pi/6)*589
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