Asked by sara
The 1.4 kg, 40-cm-diameter disk in the figure below is spinning at 260 rpm. How much friction force must the brake apply to the rim to bring the disk to a halt in 4.5 s?
Answers
Answered by
bobpursley
torque=momentinertia*ang acceleration
look up the momentInertia for a disk
ang acceleration=(260*2PI)/4.5
torque= frictionforce*radius
look up the momentInertia for a disk
ang acceleration=(260*2PI)/4.5
torque= frictionforce*radius
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