Question

A uniform disk with mass 6 kg and radius 1.8 m is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 31.5N is applied to the rim of the disk. The force direction makes an angle of 35 degree with the tangent to the rim. What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 5.9 revolution? The unit of the tangential velocity is m/s.

Answer 1

tau = I alpha
tau = Fcos35
I you'll have to look up
then lastly
omega^2 = 2 alpha θ and v = r omega

Answer 2

is £c 35 degrees???

Answer 3

i dont kno

Answer 4

123456

Answer 5

123