Question
Find the point on the graph of z = 3x^2 − y^2 at which vector n = ⟨12, 4, −1⟩ is normal to the tangent plane.
So far I've got:
fx(x,y) = 6x = 6a
fy(x,y) = -2y = -2b
Where do I go from there?
So far I've got:
fx(x,y) = 6x = 6a
fy(x,y) = -2y = -2b
Where do I go from there?