Question
Find the equations of the tangent lines to the following curves at the indicated points.
xy^2 = 1 at (1, −1)
xy^2 = 1 at (1, −1)
Answers
Reiny
xy^2 = 1
x(2y)dy/dx + y^2 (1) = 0
dy/dx = -y^2/(2xy)
at (1,-1) , dy/dx = -(-1)^2/(2(1)(-1))= 1/-2 = - 1/2
Now you have the slope and the given point. Find the
equation of the straight line, using your method of choice.
x(2y)dy/dx + y^2 (1) = 0
dy/dx = -y^2/(2xy)
at (1,-1) , dy/dx = -(-1)^2/(2(1)(-1))= 1/-2 = - 1/2
Now you have the slope and the given point. Find the
equation of the straight line, using your method of choice.