Asked by feather

find the equation of the tangent line at the given point

y=4x-3x^2 ;(2,-4)

y-(-4)=m(x-2)

what to do from here???
or is like this
3x(4x-1)^1
Answered by Steve
The slope at any point is y':
y' = 4-6x
y'(2) = -8

Now you have a slope and a point:

y+4 = -8(x-2)
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