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Find the equation of each tangent line to the curve y=(1/x) that has a slope of -1. Find each point of tangency.

1 answer

if y = 1/x
then y' = -1/x^2
given , y' = -1
-1/x^2= - 1
x^2 = 1
x = ± 1
find the corresponding y values.
You have 2 tangents, one at (1,1) , the other at (-1,-1)

Use your favourite method to find the equation of those tangents.

(The question is poorly worded when it asked for the equation of the tangent, implying there is only one)
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