Asked by Matias
How can I calculate the tangent lines at the intersection points of the y-axis?
x=4y-y^2
Answers
                    Answered by
            oobleck
            
    the intersection points are (0,0) and (0,4)
dx/dy = 4-2y
so the slope is dy/dx = 1/(4-2y)
at (0,0) the slope is 1/4
at (0,4) the slope is -1/4
makes sense, since the graph is symmetric about the line y = 2
    
dx/dy = 4-2y
so the slope is dy/dx = 1/(4-2y)
at (0,0) the slope is 1/4
at (0,4) the slope is -1/4
makes sense, since the graph is symmetric about the line y = 2
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.