Asked by anonymous

My equation for an ellipse is:
(y+6)^2 /104 + (x-46)^2/155 = 1

Would this be the co-vertices?
(46, -6 +/- squareroot 104)


Answers

Answered by Damon
Those are indeed the top and bottom of your ellipse.

of course you have them along the horizontal axis as well
x = 46 +/- sqrt 155 and y = -6
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