Asked by Anonymous
let equation of an ellipse be x^2+4y^2+6x-8y+9=0
a. Find the standard form of the ellipse
b. Find the center
c. Find the vertices
d. Find the foci
e. Find the eccentricity
a. Find the standard form of the ellipse
b. Find the center
c. Find the vertices
d. Find the foci
e. Find the eccentricity
Answers
Answered by
Steve
x^2+4y^2+6x-8y+9=0
x^2+6x + 4y^2-8y = -9
x^2+6x+9 + 4y^2-8y+4 = -9+9+4
(x+3)^2 + 4(y-1)^2 = 4
(x+3)^2/4 + (y-1)^1 = 1
Now the rest should be easy. Come on back if you get stuck.
x^2+6x + 4y^2-8y = -9
x^2+6x+9 + 4y^2-8y+4 = -9+9+4
(x+3)^2 + 4(y-1)^2 = 4
(x+3)^2/4 + (y-1)^1 = 1
Now the rest should be easy. Come on back if you get stuck.
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