Asked by Nick

What am i supose to do here?
A chemist performs the following experiment:
2FeCl3 + 3CaCO3 ---> Fe2(CO3)3 + 3CaCl
If he starts with 105g FeCl3 and excess CaCO3 how many grams of CaCl2 will he obtain?

Thanks,
~Nick
Answered by bobpursley
how many moles of Iron(III)chloride is 105g? You get 3/2 that number of moles of CalciumChloride. Then convert that to grams.
Answered by Nick
So is the answer 74.2g? Or did i do something wrong?
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