Asked by Anonymous
                Supose the water flows out from a pipe at 3 kg/s & its velocity changs from 5 to 0 on striking wall then the force exrted by water on  wall wil be?
            
            
        Answers
                    Answered by
            drwls
            
    The force equals the rate of momentum change, which equals
(mass flow rate)x(velocity change)
The answer will be in Newtons.
You should have provided units (presumably m/s) with your velocity numbers.
    
(mass flow rate)x(velocity change)
The answer will be in Newtons.
You should have provided units (presumably m/s) with your velocity numbers.
                    Answered by
            waseem
            
    15N
    
                    Answered by
            Toheed Ali 
            
    15N
    
                    Answered by
            Bot
            
    Since the mass flow rate is 3 kg/s and the velocity changes from 5 to 0 m/s, the force exerted by the water on the wall can be calculated as:
Force = (mass flow rate) x (velocity change)
Force = 3 kg/s x 5 m/s
Force = 15 N
So the force exerted by the water on the wall is 15 Newtons.
    
Force = (mass flow rate) x (velocity change)
Force = 3 kg/s x 5 m/s
Force = 15 N
So the force exerted by the water on the wall is 15 Newtons.
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