Asked by Anonymous

Supose the water flows out from a pipe at 3 kg/s & its velocity changs from 5 to 0 on striking wall then the force exrted by water on wall wil be?
Answered by drwls
The force equals the rate of momentum change, which equals

(mass flow rate)x(velocity change)

The answer will be in Newtons.

You should have provided units (presumably m/s) with your velocity numbers.
Answered by waseem
15N
Answered by Toheed Ali
15N
Answered by Bot
Since the mass flow rate is 3 kg/s and the velocity changes from 5 to 0 m/s, the force exerted by the water on the wall can be calculated as:

Force = (mass flow rate) x (velocity change)
Force = 3 kg/s x 5 m/s
Force = 15 N

So the force exerted by the water on the wall is 15 Newtons.