Asked by Jessica

Earth orbits the sun at an average distance of about 150 million kilometres every 365.2564 mean solar days, or one sidereal year. What is the linear velocity of th3 Earth in kilometres per hour?
Answered by Damon
R = 1.50* 10^8 km
circumference= 2 pi*1.50*10^8 = 9.42*10^8 km

T =365.2564 * 24 = 8766 hours = 8.766*10^3
so

v = C/T = (9.42/8.766)10^5 = 1.075*10^5
= 107,500 km/hr
Answered by bobpursley
what is w*radius?
w=PI*2*r/365 days
convert days to hours (365*24)
Answered by Jessica
Damon, why did you find the circumference when we already have the distance?
Answered by Damon
The velocity is perpendicular to the radius. It is tangent to the circle which is 2 pi R around.
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