Ask a New Question

Question

Given that Earth orbits the Sun with a semimajor axis of 1.000 AU and an approximate orbital period of 365.24 days, determine the mass of the Sun. (1 AU = 1.496 ✕ 1011 m)
7 years ago

Answers

Damon
G = 6.674*10^-11

F =G m M/r^2 = m v^2/r

G M= v^2 r

M = v^2 r/G

but v = 2 pi r/(365.24*24*3600)
7 years ago

Related Questions

The earth orbits the sun once a year (3.16 multiplied by 10^7 s) in a nearly circular orbit radius 1... The earth orbits the sun once a year (3.16 10^7 s) in a nearly circular orbit radius 1.50 10^11 m. W... The earth orbits the sun once a year (3.16 107 s) in a nearly circular orbit radius 1.50 1011 m. W... The Earth orbits the Sun once every 365 days. The distance between the Earth and the Sun is 1.5 x 1... The earth orbits the sun once every 365.24 days. The distance between the earth and sun is 1.49x 10^... The Earth orbits the Sun once per year.What is the centripetal force keeping the Earth in orbit?... Earth orbits the sun once every 365.25 days. Find the average angular speed of Earth about the sun... 24. As the Earth orbits the Sun, and the Moon orbits the Earth, they will align at a right angle eve... A. Earth orbits the sun in less than 365 days. A. Earth orbits the sun in less than 365 days. B. E... earth orbits the sun because
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use