Asked by nick
The earth orbits the sun once a year (3.16 multiplied by 10^7 s) in a nearly circular orbit radius 1.50 multiplied by 10^11 m. With respect to the sun, determine the following.
(a) the angular speed of the earth
(a) the angular speed of the earth
Answers
Answered by
Damon
omega = 2 pi radians / (3.16*10^7 seconds)
then when it asks for the linear speed (part b no doubt), that is omega * r
= [2 pi/3.16*10^7](1.5*10^11] m/s
then when it asks for the linear speed (part b no doubt), that is omega * r
= [2 pi/3.16*10^7](1.5*10^11] m/s
Answered by
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