Asked by Mary
A satellite orbits the Earth in an orbits 750 km high. Find (*) the satellite's orbital speed and (**) period. (The mass and radius of the Earth are 5.98E + 24 kg and 6370000 m, respectively.)
Answers
Answered by
Scott
the centripetal force (m v^2 / r)
is equal to the gravitational force
... G M m / r^2
v^2 = G M / r
... = 6.67E-11 * 5.98E24 / 7.12E6
the period is the speed divided into the orbital circumference
is equal to the gravitational force
... G M m / r^2
v^2 = G M / r
... = 6.67E-11 * 5.98E24 / 7.12E6
the period is the speed divided into the orbital circumference
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