Asked by Johnny

3AgNO3 + Na3PO4 ---> Ag3PO4 + 3NaNO3

Silver nitrate and sodium phosphate are reacted in equal amounts of 200. g each. How many grams of silver phosphate are produced?

1. What is the limiting?
2. How much silver phosphate is produced?
3. How much is in excess?
Answered by bobpursley
figure out how many moles of each you have.
Then, multiply the moles of silver phosphate by three. Do you have that much or more of silver nitrate? If so, you have silver nitrate in excess, and the limiting reqeant is sodum phosphate. If the reverse is true, then silver nitrate is the limiting reqeant.
silver phosphate is produced this way, pick the limiting regeant. If it is sodum phosphat, you get the same number of moles of silver phosphate. If silver nitrate is the limiting reageant, then you get 1/3 of thos moles.
Answered by Mike
Hi bob!

Would you mind explaining this one too. Not sure I understand how to solve this one still. These are some of my first limited reagent questions I’ve ever done. Thanks!
Answered by bobpursley
do the steps I outlined, in order.
Moles silver nitrate
moles sodum phosphate.
Then
which is the moles silver phosphate greater than 3x moles silver nitrate?
limiting reageant?
then product will be ? same/or 3x?
I will be happy to critique your work.
Answered by Johnny
Ok this is what I got so far:

200gAgNO3= 1.18 mole AgNO3
200gNa3PO4= 1.22 mole NaPO4

Then 419g Ag3PO4 x3 = 1257Ag3PO4

limiting reagent- Ag3PO4?
Answered by Mike
Hi bob!

Would you mind explaining this one too. Not sure I understand how to solve this one still. These are some of my first limited reagent questions I’ve ever done. Thanks!
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