you need the balanced equation:
2Na3PO4 + 3BaCl2 --> Ba3(PO4)2 + 6NaCl
So, each 2 moles of Na3PO4 yields 1 mole of Ba3(PO4)2
If 0.50 mol of Na3PO4 is mixed with 0.30 mol
of BaCl2, the maximum number of moles of barium
phosphate which can be formed is:
How do i set up the problem?
1 answer