Asked by Anonymous
If 0.50 mol of Na3PO4 is mixed with 0.30 mol
of BaCl2, the maximum number of moles of barium
phosphate which can be formed is:
How do i set up the problem?
of BaCl2, the maximum number of moles of barium
phosphate which can be formed is:
How do i set up the problem?
Answers
Answered by
Steve
you need the balanced equation:
2Na3PO4 + 3BaCl2 --> Ba3(PO4)2 + 6NaCl
So, each 2 moles of Na3PO4 yields 1 mole of Ba3(PO4)2
2Na3PO4 + 3BaCl2 --> Ba3(PO4)2 + 6NaCl
So, each 2 moles of Na3PO4 yields 1 mole of Ba3(PO4)2
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