Question

If 0.50 mol of Na3PO4 is mixed with 0.30 mol
of BaCl2, the maximum number of moles of barium
phosphate which can be formed is:

How do i set up the problem?

Answer 1

you need the balanced equation:

2Na3PO4 + 3BaCl2 --> Ba3(PO4)2 + 6NaCl

So, each 2 moles of Na3PO4 yields 1 mole of Ba3(PO4)2