How many grams of na3po4 will be needed to produce 425ml of a solution that has a concentration of na+ ions of 1.30 M?

Answer 1

Na^+ = 1.30 M
Na3PO4 = 1.30/3 since there are 3 Na^+ in 1 molecule of Na3PO4.
M = moles/L
Substitute M and L; solve for moles.

Then moles = grams/molar mass.
You have moles and molar mass; solve for grams.
In the future remember that na3po4 doesn't mean a thing; it's Na3PO4.

Answer 2

30.2 g

Answer 3

I agree.