Asked by James
How many grams of na3po4 will be needed to produce 425ml of a solution that has a concentration of na+ ions of 1.30 M?
Answers
Answered by
DrBob222
Na^+ = 1.30 M
Na3PO4 = 1.30/3 since there are 3 Na^+ in 1 molecule of Na3PO4.
M = moles/L
Substitute M and L; solve for moles.
Then moles = grams/molar mass.
You have moles and molar mass; solve for grams.
In the future remember that na3po4 doesn't mean a thing; it's Na3PO4.
Na3PO4 = 1.30/3 since there are 3 Na^+ in 1 molecule of Na3PO4.
M = moles/L
Substitute M and L; solve for moles.
Then moles = grams/molar mass.
You have moles and molar mass; solve for grams.
In the future remember that na3po4 doesn't mean a thing; it's Na3PO4.
Answered by
James
30.2 g
Answered by
DrBob222
I agree.
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