Asked by jhong
3Ag(s) + 4HNO3(AQ) = 3AGNO3(aq) + NO(g) + 2h2o(l)
How many moles of NO can be produced by the reaction of 54.0g of Ag
show me the step please
How many moles of NO can be produced by the reaction of 54.0g of Ag
show me the step please
Answers
Answered by
DrBob222
mols Ag = grams/molar mass = ?
The coefficients tell you exactly how much NO you get. You get 1 mol NO for every 3 mols Ag; therefore,
mols NO = ?mols Ag x (1 mol NO/3 mol Ag) = ?mols x (1/3) = xx mol NO.
The coefficients tell you exactly how much NO you get. You get 1 mol NO for every 3 mols Ag; therefore,
mols NO = ?mols Ag x (1 mol NO/3 mol Ag) = ?mols x (1/3) = xx mol NO.
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