mols Ag = grams/molar mass = ?
The coefficients tell you exactly how much NO you get. You get 1 mol NO for every 3 mols Ag; therefore,
mols NO = ?mols Ag x (1 mol NO/3 mol Ag) = ?mols x (1/3) = xx mol NO.
3Ag(s) + 4HNO3(AQ) = 3AGNO3(aq) + NO(g) + 2h2o(l)
How many moles of NO can be produced by the reaction of 54.0g of Ag
show me the step please
1 answer