Question

A spring (k = 857 N/m) is hanging from the ceiling of an elevator, and a 5.9 kg object is attached to the lower end. By how much does the spring stretch (relative to its unstrained length) when the elevator is accelerating upward at a = 0.81 m/s2?



force= kx
mg+ma=kx
solve for a.

Answer 1

Use kx=mg+ma
857x = (5.9*9.8) + (5.9*.81)
thus, x= .073