Asked by Anonymous
                A golf ball of mass 50.0 grams is at rest on a tee.  It is struck by a golf club with an average force of 850 Newtons.  The ball accelerates to a speed of 68.0 m/sec.  How long was the club in contact with the ball?
            
            
        Answers
                    Answered by
            Henry
            
    F = M*a.
a = F/M = 850/0.05kg = 17,000 m/s^2.
V = Vo + a*t = 68 m/s.
0 + 17,000t = 68,
t = 0.004 s.
    
a = F/M = 850/0.05kg = 17,000 m/s^2.
V = Vo + a*t = 68 m/s.
0 + 17,000t = 68,
t = 0.004 s.
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