Asked by Anonymous
A golf ball of mass 50.0 grams is at rest on a tee. It is struck by a golf club with an average force of 850 Newtons. The ball accelerates to a speed of 68.0 m/sec. How long was the club in contact with the ball?
Answers
Answered by
Henry
F = M*a.
a = F/M = 850/0.05kg = 17,000 m/s^2.
V = Vo + a*t = 68 m/s.
0 + 17,000t = 68,
t = 0.004 s.
a = F/M = 850/0.05kg = 17,000 m/s^2.
V = Vo + a*t = 68 m/s.
0 + 17,000t = 68,
t = 0.004 s.
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