Asked by Corey
A golf ball of mass 0.05 kg is struck by a golf club of mass m kg with a speed of 50m/s will have an initial speed of v(m)=83m/(m+0.05) m/s. show that v'(m)>0 and interpret this result in context with the application. Compare v'(0.15) and v'(0.20) in context of the application as well.
Answers
Answered by
Steve
v(m) = 83m / (m+0.05)
dv/dm = 1660/(20x+1)^2 = 4.15/(x+0.05)^2
clearly v' > 0
v(m) = 83 - 83/(20m+1)
clearly the maximum possible initial velocity is 83m/s, which is achievable only with a golf club of infinite mass.
naturally, a heavier club hits the ball faster
dv/dm = 1660/(20x+1)^2 = 4.15/(x+0.05)^2
clearly v' > 0
v(m) = 83 - 83/(20m+1)
clearly the maximum possible initial velocity is 83m/s, which is achievable only with a golf club of infinite mass.
naturally, a heavier club hits the ball faster
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.