Asked by Anonymous

A golf ball of mass 4.6 g is struck by a golf club at a speed of 50 m/s. The ball has inital velocity ,v, in metres per second, of v(m) = 83/(m+0.046), where m is the mass, in grams, of the golf club. Describe the rate of change of the initial velocity as the mass of the club increases. Show your work.

15 years ago