Question
A golf ball has a mass of 0.05 kg and acquires a speed of 80.0 m/s when hit with a force of 3000 N. how long was the club in contact with the golf ball?
Answers
drwls
(Force)*(Contact time) = (Change in momentum) = 0.05*80 = 4.0 kg*m/s
Contact time
= (4.0 kg*m/s)/(3000 kg*m/s^2)
= 1.33*10^-3 s
Contact time
= (4.0 kg*m/s)/(3000 kg*m/s^2)
= 1.33*10^-3 s