Ask a New Question

Question

A golf ball of mass 0.05 kg struck by a golf club of mass 𝑚 kg with speed 50 𝑚/𝑠 will have
an initial speed of 𝑢(𝑚) =
83𝑚
𝑚+0.05
m/s. Verify that 𝑢
′
(𝑚) > 0. Compare 𝑢′(0.15) and
𝑢′(0.20) in terms of the speed and mass of the ball.
4 years ago

Answers

oobleck
that copy/paste isn't working out so well, is it?
if u(m) = 83m+0.5
then u'(m) = 83

I suspect a typo, since you said it had an initial speed of 50 m/s
Maybe you can clear things up a bit ...
4 years ago

Related Questions

The mass of a golf ball is 45.9g. If it leaves the tee with a speed of 72.0 m/s, what is its corresp... The mass of a golf ball is 45.9g . If it leaves the tee with a speed of 80.0m/s , what is its corres... A golf ball of mass 4.6 g is struck by a golf club at a speed of 50 m/s. The ball has inital velocit... A golf ball of mass 0.045 kg is hit off the tee at a speed of 48 m/s. The golf club was in contact w... A golf ball (mass 0.045 kg) is hit with a club from a tee. The plot shows the force on the ball as a... A golf ball of mass 4.50 10-2 kg is struck by a club. Contact lasts 2.35 10-4 s, and the ball leav... A golf ball has a mass of 0.05 kg and acquires a speed of 80.0 m/s when hit with a force of 3000 N.... A golf ball of mass 0.05 kg struck by a golf club of mass 𝑚 kg with speed 50 𝑚/𝑠 will have an initia... A golf ball of mass 45.9 g is launched from a height of 8.0 m above the level of the green at a spe...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use