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Original Question
if you have 55.6 grams of nitrate ions in a compound that consists of nitrate ions and plumbous ions, how many grams of the com...Asked by lyne
if you have 55.6 grams of nitrate ions in a compound that consists of nitrate ions and plumbous ions, how many grams of the compound do you have?
how do i do this problem im completely stuck!?
how do i do this problem im completely stuck!?
Answers
Answered by
DrBob222
Pb(NO3)2.
mols NO3^- = 55.6/molar mass NO3^- = ??
mols Pb(NO3)2 = mols NO3^- x (1 mol Pb(NO3)2/2 mols NO3^-) = ??
grams Pb(NO3)2 = mols plumbous nitrate X molar mass plumbous nitrate.
mols NO3^- = 55.6/molar mass NO3^- = ??
mols Pb(NO3)2 = mols NO3^- x (1 mol Pb(NO3)2/2 mols NO3^-) = ??
grams Pb(NO3)2 = mols plumbous nitrate X molar mass plumbous nitrate.
Answered by
GK
<b>Why two postings of the same question?</b>
You have an answer at:
http://www.jiskha.com/display.cgi?id=1228951921
You have an answer at:
http://www.jiskha.com/display.cgi?id=1228951921
Answered by
lyne
thanks sorry i posted it again when i didn't get an answer for a long time
thanks again
thanks again