if you have 55.6 grams of nitrate ions in a compound that consists of nitrate ions and plumbous ions, how many grams of the compound do you have?

Question

how do i do this problem im completely stuck!?

Answer 1

The formula of the compound form from Pb^2+ and NO3^-1 ions is Pb(NO3)2.

To answer the question,find the formula masses of Pb(NO3)2 and (NO3) times 2 .

grams Pb(NO3)2 = [Pb(NO3)2 / (NO3)(2)](55.6g)

Answer 2

Would that consist also of 54.4 grams of plumbous ions, or no?