Asked by Chris
How many grams of lithium nitrate, LiNO3, are required to prepare 3.00 × 102 mL of 2.00 × 10–1 M solution?
Answers
Answered by
DrBob222
M = moles/L
solve for moles.
moles = grams/molar mass
solve for grams.
solve for moles.
moles = grams/molar mass
solve for grams.
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