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Asked by Chris

How many grams of lithium nitrate, LiNO3, are required to prepare 3.00 × 102 mL of 2.00 × 10–1 M solution?
15 years ago

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Answered by DrBob222
M = moles/L
solve for moles.

moles = grams/molar mass
solve for grams.
15 years ago
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How many grams of lithium nitrate, LiNO3, are required to prepare 3.00 × 102 mL of 2.00 × 10–1 M solution?

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