Asked by Adam
Two blocks lie on a triangle as shown in the figure. Block m has a mass of 5 kg and block P has a mass of 14 kg. Assume the inclines and pulleys are frictionless find the tension in the string.
They lie with the string resting on the peak of a 110 degree obtuse triangle, each side corner of the triangle measuring 35 degress
They lie with the string resting on the peak of a 110 degree obtuse triangle, each side corner of the triangle measuring 35 degress
Answers
Answered by
bobpursley
Ok, I am visulizing two inclines back to back, with a pulley at the top, and masses on each side.
on each block, the gravity component DOWN the plane is
mg*cos35
No resistive force (friction).
so first, find the motion.
Net force=(14-5)*9.8*cos35 twoward the greater mass.
net force=totamass*acceleration
acceleration=(14-5)*9.8*cos35 /19
Now knowing acceleration, one can get tension. Examine either block, here is the smaller block.
Tension-5*9.8*cos35=5*acceleration
solve for tension.
on each block, the gravity component DOWN the plane is
mg*cos35
No resistive force (friction).
so first, find the motion.
Net force=(14-5)*9.8*cos35 twoward the greater mass.
net force=totamass*acceleration
acceleration=(14-5)*9.8*cos35 /19
Now knowing acceleration, one can get tension. Examine either block, here is the smaller block.
Tension-5*9.8*cos35=5*acceleration
solve for tension.
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