Question

Two blocks, m1 = 4 kg and m2 = 2 kg, are in contact with each other and are on a horizontal surface for which the coefficient of kinetic friction is 0.1. A 34 N horizontal force acts on block 1, making both blocks move in the direction of block 2. 34N --> (m1)(m2) -->

Find:
a) the acceleration of the blocks
b) the force exerted by m2 on m1.

I have Ff(total) = 5.88N => Fnet = ma => a = 4.6866m/s2

I don't konw how to do b)

Answer 1

net force=total mass*a
34-(m1+m2)g*mu=(m1+m2)a
solve for a

force on 2:
you know a.
net force=m2*a
F-m2*g*mu=m2*a
solve for F