Question

Two blocks m1 = 9.1 kg and m2 = 5.6 kg are connected by a homogeneous rope that has a mass of mr = 1.50 kg. A constant vertical force, F = 193.0 N, is applied to the upper block. What is the magnitude of the acceleration of the system?What is the magnitude of the tension in the rope at the bottom end of the rope?

Answer 1

assume the rope does not stretch
total mass = 9.1+1.5+5.6 = 16.2
total weight = 16.2*9.81 = 158.9 N
acceleration of system = a
a = (193 -158.9)/16.2
a = 2.1 m/s^2

I do not know mass of lower block so call it m
force down = 9.81 m
force up = tension T
acceleration up = 2.1
T - 9.81 m = m (2.1)
T = m (2.1+9.81)